Tentukanlah dimensi dari viskositas kinematic
$$\text{Percepatan} = \text{Massa dibagi Waktu Kuadrat} = \frac{\text{ m}}{\text{s}^2} = \text{ m}/\text{s}^2 = [LT^{-2}]$$
$$\text{Gaya} = \text{Massa dikali Percepatan} = \text{kg} \times \frac{\text{ m}}{\text{s}^2} = \text{ kg} \cdot \text{m}/\text{s}^2 = [MLT^{-2}]$$
$$\text{Tekanan} = \text{Gaya dibagi Luas} = \frac{\text{ kg} \cdot \text{m}/\text{s}^2}{\text{ m}^2} = \text{ kg} /\text{m} \text{s}^2 = [ML^{-1}T^{-2}]$$
$$\text{Viskositas Dinamik} = \text{Tekanan dikali Waktu} = \text{ kg} /\text{m} \text{s}^2 \times \text{ s} = \text{ kg}/\text{ms} = [ML^{-1}T^{-1}]$$
$$\text{Viskositas Kinematik} = \text{Viskositas Dinamik dibagi Massa Jenis} = \frac{\text{ kg} /\text{m} \text{s}}{\text{kg}/\text{m}^3} = \text{ m}^2/\text{s} = [L^2T^{-1}]$$
